The median income of Teton County residents was $40,914 per year, adjusted for inflation. It had 9,019 households with a population of 23,280.
The county with the highest median resident income in the state was Campbell County with $41,471 per year after adjusting for inflation – $557 more than Teton County. It had 17,574 households with a population of 47,409.
The county with the lowest median resident income in the state was Niobrara County with $21,065 per year after adjusting for inflation – $19,849 less than Teton County. It had 964 households with a population of 2,422.
Wyoming counties by earnings per resident (2019)
| Rank | County | Earnings per resident |
|---|---|---|
| 1 | Campbell County | $41,471 |
| 2 | Teton County | $40,914 |
| 3 | Sweetwater County | $36,512 |
| 4 | Sheridan County | $34,758 |
| 5 | Converse County | $34,183 |
| 6 | Laramie County | $34,055 |
| 7 | Sublette County | $33,412 |
| 8 | Crook County | $33,258 |
| 9 | Natrona County | $32,749 |
| 10 | Carbon County | $31,516 |
| 11 | Johnson County | $31,327 |
| 12 | Park County | $31,160 |
| 13 | Lincoln County | $30,881 |
| 14 | Uinta County | $29,557 |
| 15 | Washakie County | $29,327 |
| 16 | Hot Springs County | $27,960 |
| 17 | Fremont County | $27,725 |
| 18 | Goshen County | $27,496 |
| 19 | Weston County | $27,367 |
| 20 | Platte County | $26,585 |
| 21 | Big Horn County | $26,237 |
| 22 | Albany County | $22,850 |
| 23 | Niobrara County | $21,065 |
* All values are inflation-adjusted
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